Monday, Mr. C stacked a display case of 80 heads of lettuce. By end of day, some were sold.

Tuesday Mr. C counted lettuce left and decided to add an equal number of lettuce (**hint - he doubled the leftovers).  At end of Tuesday, he sold the same number as Monday.

Wednesday Mr. C tripled lettuce left. He sold the same number that day too. At end of day, there were no lettuce left.

How manylettuce were sold each day?

Please help, I would appreciate guidance on this.
Thx

if he started with h heads of lettuce, and sold s,

end of Monday he had h-s
on Tuesday, he had 2(h-s) and sold s, leaving 2h-3s
On Wednesday, he had 3(2h-3s) and sold s, leaving 0.

6h-9s-s = 0
6h = 10s

So, he started out with some multiple of 10 and 6, let's say 30

h=5,s=3
Monday: start with 5, sold 3, leaving 2
Tuesday: start with 4, sold 3, leaving 1
Wednesday: start with 3, sold 3.

Or, he could have started out with

150, so h=25, s=15
Monday: start with 25, sold 15, leaving 10
Tuesday: start with 20, sold 15, leaving 5
Wednesday: start with 15, sold 15.

Oops. I forgot that he started with 80.

So,

6*80 = 10s
s = 48

Start with 80, sold 48, leaving 32
Tuesday: start with 64, sold 48, leaving 16
Wednesday: start with 48, sold 48.

Thanks!This really helped

To figure out how many lettuce were sold each day, we can follow these steps:

1. Let's assume that the number of lettuce sold on Monday is "x".

2. On Tuesday, Mr. C doubled the amount of leftover lettuce. This means that the number of lettuce left on Tuesday is 80 - x (as he started with 80 heads of lettuce and sold x heads of lettuce on Monday). Now, Mr. C adds an equal number of lettuce, which is also 80 - x. Therefore, the total number of lettuce on Tuesday is (80 - x) + (80 - x) = 160 - 2x.

3. Since Mr. C sold the same number of lettuce on Tuesday as on Monday, we can now equate the two values: x = (160 - 2x).

4. Solving this equation, we get: 3x = 160, which simplifies to x = 53.33. However, since we cannot have a fraction of a head of lettuce, we round down to the nearest whole number. Therefore, x = 53.

5. Now, we know that Mr. C sold 53 heads of lettuce on Monday. Using this information, we can find the number of lettuce left on Tuesday: 80 - 53 = 27 heads of lettuce.

6. On Wednesday, Mr. C tripled the amount of leftover lettuce, which means there were 27 x 3 = 81 heads of lettuce. Since he sold the same number on Wednesday as on Monday (53 heads of lettuce), the 81 heads of lettuce were sold on Wednesday.

Therefore, the number of lettuce sold each day is:
Monday: 53
Tuesday: 53
Wednesday: 81