Posted by **John** on Monday, October 22, 2012 at 6:04pm.

Monday, Mr. C stacked a display case of 80 heads of lettuce. By end of day, some were sold.

Tuesday Mr. C counted lettuce left and decided to add an equal number of lettuce (**hint - he doubled the leftovers). At end of Tuesday, he sold the same number as Monday.

Wednesday Mr. C tripled lettuce left. He sold the same number that day too. At end of day, there were no lettuce left.

How manylettuce were sold each day?

Please help, I would appreciate guidance on this.

Thx

- Math -
**Steve**, Monday, October 22, 2012 at 6:24pm
if he started with h heads of lettuce, and sold s,

end of Monday he had h-s

on Tuesday, he had 2(h-s) and sold s, leaving 2h-3s

On Wednesday, he had 3(2h-3s) and sold s, leaving 0.

6h-9s-s = 0

6h = 10s

So, he started out with some multiple of 10 and 6, let's say 30

h=5,s=3

Monday: start with 5, sold 3, leaving 2

Tuesday: start with 4, sold 3, leaving 1

Wednesday: start with 3, sold 3.

Or, he could have started out with

150, so h=25, s=15

Monday: start with 25, sold 15, leaving 10

Tuesday: start with 20, sold 15, leaving 5

Wednesday: start with 15, sold 15.

- Math -
**Steve**, Monday, October 22, 2012 at 6:26pm
Oops. I forgot that he started with 80.

So,

6*80 = 10s

s = 48

Start with 80, sold 48, leaving 32

Tuesday: start with 64, sold 48, leaving 16

Wednesday: start with 48, sold 48.

- Math -
**Anonymous**, Thursday, October 25, 2012 at 8:12pm
Thanks!This really helped

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