Math
posted by John on .
Monday, Mr. C stacked a display case of 80 heads of lettuce. By end of day, some were sold.
Tuesday Mr. C counted lettuce left and decided to add an equal number of lettuce (**hint  he doubled the leftovers). At end of Tuesday, he sold the same number as Monday.
Wednesday Mr. C tripled lettuce left. He sold the same number that day too. At end of day, there were no lettuce left.
How manylettuce were sold each day?
Please help, I would appreciate guidance on this.
Thx

if he started with h heads of lettuce, and sold s,
end of Monday he had hs
on Tuesday, he had 2(hs) and sold s, leaving 2h3s
On Wednesday, he had 3(2h3s) and sold s, leaving 0.
6h9ss = 0
6h = 10s
So, he started out with some multiple of 10 and 6, let's say 30
h=5,s=3
Monday: start with 5, sold 3, leaving 2
Tuesday: start with 4, sold 3, leaving 1
Wednesday: start with 3, sold 3.
Or, he could have started out with
150, so h=25, s=15
Monday: start with 25, sold 15, leaving 10
Tuesday: start with 20, sold 15, leaving 5
Wednesday: start with 15, sold 15. 
Oops. I forgot that he started with 80.
So,
6*80 = 10s
s = 48
Start with 80, sold 48, leaving 32
Tuesday: start with 64, sold 48, leaving 16
Wednesday: start with 48, sold 48. 
Thanks!This really helped