posted by Angela .
A 5.9 g coin sliding to the right at 27.6 cm/s makes an elastic head-on collision with a 17.7 g coin that is initially at rest. After the collision, the 5.9 g coin moves to the left at 13.8 cm/s.
(a) Find the final velocity of the other coin.
(b) Find the amount of kinetic energy transferred to the 17.7 g coin.
The answer to (a) is 13.8.... can't get(b)
v₂= 2m₁v₁₀/(m₁+m₂) =2•5.9•27.6/(5.9+17.7)=13.8 cm/s
(b) KE1(fin) –KE1(init) =m₁ •v₁₀²/2 –m₁•v₁²/2=0.5•m₁ (v₁₀² –v₁²)=
=0.5•0.0059•(0.278²-0.138²)=1.7 •10⁻⁴ J.
KE2(fin)-KE2(init) = KE2(fin) -0 = m₂ •v₂²/2=0.0177•0.138²/2=1.7•10⁻⁴ J
are you sure the 0.138 shouldn't be .0138?? and the answer be 1.7e-6??