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March 25, 2017

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When a 0.116 kg mass is suspended at rest from a certain spring, the spring stretches 3.50 cm. Find the instantaneous acceleration of the mass when it is raised 5.70 cm, compressing the spring 2.20 cm

  • physics - ,

    m•g=k•x₁
    k= m•g/x₁=0.116•9.8/0.035= 32.5 N/m
    When the spring rises 5.7 cm =0.057 m and the spring is compressed to x₂=0.022 m
    F= k•x₂ =ma
    a =k•x₂ /m=32.5•0.022/0.116 =6.16 m/s²

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