Posted by Billy on Monday, October 22, 2012 at 12:40pm.
10000 = ae^0 --> a=10000
300000 = 10000 e^3k
30 = e^3k
3k = ln30
k = 1/3 ln30
P(t) = 10000 * e^(t/3 ln30)
P(4) = 10000 * e^(4/3 ln30) = 932170
Note that since e^ln30 = 30,
P(t) = 10000 * 30^(t/3)
but to evaluate that, you need to fall back to logs anyway.
What it means is that the population grows by a factor of 30 every 3 years. But then, we knew that from the initial conditions given: P(3) = 30*P()
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