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August 30, 2014

August 30, 2014

Posted by **Soren** on Monday, October 22, 2012 at 12:25pm.

x=h+ asecQ

y=k+ tanQ

- Math -
**Steve**, Monday, October 22, 2012 at 2:43pmsecθ = (x-h)/a

tanθ = (y-k)

since sec^2 θ = 1+tan^2 θ

(x-h)^2/a^2 = 1+(y-k)^2

or,

(x-h)^2/a^2 - (y-k)^2 = 1

which is a horizontal hyperbola centered at (h,k).

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