Posted by **Lopez** on Monday, October 22, 2012 at 5:42am.

Your projectile launching system is partially jammed. It can only launch objects with an initial vertical velocity of 42.0 m/s, though the horizontal component of the velocity can vary. You need your projectile to land 214 m from its launch point. What horizontal velocity do you need to program into the system?

- physics -
**Steve**, Monday, October 22, 2012 at 10:39am
the height is

h(t) = 42t - 4.9t^2 = t(42-4.9)

h=0 when t=8.57

so, after 8.57 seconds, the horizontal distance traveled is 214m. Since the horizontal component dies not change (much)

Vx = 214m/8.57s = 25 m/s

- physics -
**Jaclyn**, Friday, June 14, 2013 at 11:21pm
How did you come up with 4.9t^2?

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