Friday

July 25, 2014

July 25, 2014

Posted by **Lopez** on Monday, October 22, 2012 at 5:42am.

- physics -
**Steve**, Monday, October 22, 2012 at 10:39amthe height is

h(t) = 42t - 4.9t^2 = t(42-4.9)

h=0 when t=8.57

so, after 8.57 seconds, the horizontal distance traveled is 214m. Since the horizontal component dies not change (much)

Vx = 214m/8.57s = 25 m/s

- physics -
**Jaclyn**, Friday, June 14, 2013 at 11:21pmHow did you come up with 4.9t^2?

**Related Questions**

PHYSICS - The launching velocity of a projectile is 20 m/s at 53 degrees above ...

Physics- i need to know how to do these problems - Two projectiles are launched ...

Physics - A projectile, fired with unknown initial velocity, lands 20.8 s later ...

physics - A projectile, fired with unknown initial velocity, lands 18.4 s later ...

Physics - The velocity of a projectile at launch has a horizontal component v_h ...

Physics - A projectile is shot from the ground at an angle of 60 degrees with ...

Physics - A projectile is shot from the ground at an angle of 60 degrees with ...

physics - A projectile is launched over level ground at a launch angle of 70o ...

physics - A projectile of mass 0.777 kg is shot from a cannon, at height 6.6 m...

Basic Phsyics - A projectile is fired such that the vertical component of its ...