you throw a ball upwards in the air at a velocity of 80m/s how fast will it be moving at 3 sec?
240 m/s assuming that the ball is not at the maximum
To find the velocity of the ball at any given time, we can use the equation of motion:
v = u + at
where:
v = final velocity
u = initial velocity
a = acceleration
t = time
However, it is important to note that the acceleration due to gravity will cause the ball's velocity to change direction. Therefore, we need to consider that the initial velocity (u) in this case is positive (+80 m/s) for the upward direction, and the acceleration (a) due to gravity is constant and negative (-9.8 m/s²).
Let's plug the values into the equation:
v = u + at
v = 80 m/s + (-9.8 m/s²) * 3 s
v = 80 m/s - 29.4 m/s
v ≈ 50.6 m/s (rounded to the nearest tenth)
Therefore, at 3 seconds, the ball will be moving downwards with a velocity of approximately 50.6 m/s.
To determine the velocity of the ball at a given time, we can use the equation for the velocity of an object under constant acceleration:
v = u + at
where:
- v is the final velocity,
- u is the initial velocity,
- a is the acceleration, and
- t is the time.
In this case, the ball is thrown upward, so the acceleration is due to gravity, which is approximately -9.8 m/s² (negative because it acts in the opposite direction of motion). The initial velocity u is 80 m/s (upward) since the ball is thrown upwards.
To find the velocity at 3 seconds, we substitute the known values into the equation:
v = 80 m/s + (-9.8 m/s²) × 3 s
Calculating this equation will give us the velocity of the ball at 3 seconds.