Posted by **reba** on Sunday, October 21, 2012 at 9:17pm.

the perimeter of a dog park is 156 ft. If the length of the park is 2 ft. less than 3 times the width, what are the dimensions of the dog park?

- math -
**Reiny**, Sunday, October 21, 2012 at 9:28pm
width ---- w

length ---- 3w - 2

2w + 2(3w-2) = 156

2w + 6w - 4 = 156

8w = 160

w = 20

park is 20 by 58

- math -
**Jane**, Sunday, October 21, 2012 at 9:30pm
The dimensions of the dog part are 20ft by 56 ft.

Set up the problem

w + w + ( 3w - 2 ) + ( 3w - 2 ) = 156

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**Ms. Sue**, Sunday, October 21, 2012 at 9:31pm
P = 2L + 2W

156 = 2(3W - 2) + 2W

156 = 6W - 4 + 2W

160 = 8W

20 = W

~~~~~~~~~~~~~~~~`

L = 58

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**Jane**, Sunday, October 21, 2012 at 9:32pm
sorry I post 56 instead of 58, the dimensions are 20ft by 58ft

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