Posted by reba on Sunday, October 21, 2012 at 9:17pm.
the perimeter of a dog park is 156 ft. If the length of the park is 2 ft. less than 3 times the width, what are the dimensions of the dog park?

math  Reiny, Sunday, October 21, 2012 at 9:28pm
width  w
length  3w  2
2w + 2(3w2) = 156
2w + 6w  4 = 156
8w = 160
w = 20
park is 20 by 58

math  Jane, Sunday, October 21, 2012 at 9:30pm
The dimensions of the dog part are 20ft by 56 ft.
Set up the problem
w + w + ( 3w  2 ) + ( 3w  2 ) = 156

math  Ms. Sue, Sunday, October 21, 2012 at 9:31pm
P = 2L + 2W
156 = 2(3W  2) + 2W
156 = 6W  4 + 2W
160 = 8W
20 = W
~~~~~~~~~~~~~~~~`
L = 58

math  Jane, Sunday, October 21, 2012 at 9:32pm
sorry I post 56 instead of 58, the dimensions are 20ft by 58ft
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