Post a New Question

AP Chemistry

posted by .

What volume of 0.596M K3PO4 is required to
react with 29 mL of 0.864 M MgCl2 according to the equation

2K3PO4 + 3MgCl2 -> Mg3(PO4)2 + 6KCl

Answer in units of mL

  • AP Chemistry -

    mols MgCl2 = M x L = ?
    Use the coefficient in the balanced equation to convert mols MgCl2 to mols K3PO4.
    Then M K3PO4 = mols K3PO4/L K3PO4. You know M and mols, solve for L and colnvert to mL.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question