Posted by Kelly on Sunday, October 21, 2012 at 6:46pm.
pH + pOH = pKw = 14.
You know pH and pKw, solve for pOH, then
pOH = -log(OH^-) and solve for (OH^-).
..........BH + HOH ==> BH2^+ + OH^-
Kb = (BH2^+)(OH^-)/(BH)
You know (OH^-) = (BH2^+) and Kb, solve for (BH) = concn of base.
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