Posted by Jazmin on Sunday, October 21, 2012 at 5:42pm.
Beginning energy: 1/2 m 15^2
lost energy while slowing: mg*(cos20)*(mu)distance
gained energy while slowing: mg (d/sin20)
final energy=0
finalenergy=betinning enrgy+gained energy-lost energy
0=1/2 m 15^2+mg*d/sin20-.8 mg*(cos20)*d
solve for diistance d
The mass is not given in the problem, does that mean it cancels out?
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