Posted by **laura** on Sunday, October 21, 2012 at 2:52pm.

Suppose a shipment of 500 machine parts contains 62 defective and 438 non-defective machine parts. From the shipment you take a random sample of 25. You are interested in the number of defective machine parts out of 25 trials and corresponding probabilities.

When sampling with replacement (binomial), determine the probability of obtaining each number of defective machine parts.

I am trying to calculate the probability of getting a defective machine part.

Defective parts of out 500: 62/500=12.4%

Would the defective parts out of the 25 trials be: 25*.124=3.1

I am on the right track?? Any help or guidance would be greatly appreciated!

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