The drawing shows a jet engine suspended beneath the wing of an airplane. The weight W of the engine is 12000 N and acts as shown in the drawing. In flight the engine produces a thrust T of 54200 N that is parallel to the ground. The rotational axis in the drawing is perpendicular to the plane of the paper. With respect to this axis, find the magnitude of the torque due to each of the following forces:

a. weight
b. thrust
picture has a plane with an angle of 32 degrees between the wing and the body, and the engine thrust is parallel to the body of the plane and the weight is perpendicular to the body of the plane

(a) Torque1= W•L•sinα = 12000•2.5•sin32°=…

(b) Torque2=T•L•cosα=54200•2.5•cos32°=…

To find the magnitude of the torque due to each force, we need to consider the perpendicular distance between the axis of rotation and the line of action of each force.

a. Weight:

In the given picture, the weight W of the engine acts perpendicular to the body of the plane. To find the perpendicular distance between the axis of rotation and the line of action of the weight, we need to consider the component of the weight perpendicular to the plane.

The component of the weight perpendicular to the plane is given by W_perpendicular = W * sin(θ), where θ is the angle between the wing and the body (32 degrees).

W_perpendicular = 12000 N * sin(32 degrees)
W_perpendicular ≈ 6424.84 N

Since the perpendicular distance is equal to the distance from the axis of rotation to the line of action of the force, the magnitude of the torque due to weight can be calculated as follows:

Torque due to weight = W_perpendicular * distance

b. Thrust:

In the given picture, the thrust T of the engine acts parallel to the body of the plane. Therefore, the perpendicular distance between the axis of rotation and the line of action of the thrust is equal to zero. This means that the torque due to thrust is zero.

In summary:
a. The magnitude of the torque due to weight is W_perpendicular * distance.
b. The magnitude of the torque due to thrust is zero.

To find the magnitude of the torque due to each force, we need to use the formula for torque:

Torque = Force * Perpendicular distance

Let's break down the calculations for each force:

a. Weight:

In the given diagram, the weight (W) of the engine acts perpendicular to the body of the plane. To find the perpendicular distance, we need to determine the lever arm or the distance between the axis of rotation and the line of action of the force.

Since the weight is perpendicular to the body of the plane, the lever arm is the distance from the axis of rotation to the point where the weight force is applied.

To find the magnitude of the torque due to weight, we can use the formula:

Torque (Weight) = Weight * Distance from the axis of rotation to the weight

b. Thrust:

In the given diagram, the thrust (T) of the engine acts parallel to the ground/body of the plane. To find the perpendicular distance, we again need to determine the lever arm or the distance between the axis of rotation and the line of action of the force.

Since the thrust is parallel to the body of the plane, there is no lever arm, and the torque due to thrust is zero.

Therefore, the magnitude of the torque due to thrust is zero.

Please provide the value for the distance of the axis of rotation to the weight in order to calculate the torque due to weight accurately.