Posted by **Randi** on Saturday, October 20, 2012 at 9:19pm.

An arrow is launched upward with a velocity of 54 feet per second from the top of a 75 foot building. What is the maximum height attained by the arrow in feet?

- College Algebra -
**Reiny**, Saturday, October 20, 2012 at 11:13pm
from your information, the height h is

h = -16t^2 + 54t +75 , where t is in seconds and h is in feet

dh/dt = -32t + 54

= 0 for a max h

32t = 54

t = 54/32 = 27/16 ---> time it took to reach max height = -16(27/16)^2 + 54(27/16) + 75

= 120.56 ft

h = -16(

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