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Calc

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It is noon. A secret agent is driving a jeep through the desert in the tiny principality of Alta Loma. He is 32km from the nearest point on a straight, paved road. Down the road 16km is a power plant in which a band of international terrorists has placed a time bomb set to explode at 12:50pm. The jeep can travel at 48km/hr in the sand at 80 km/hr on a paved road. If he arrives at the power plant in the shortest possible time, how long will our hero have to diffuse the bomb?

  • Calc - ,

    Geesh, I wish authors would stick to the traditional wording of the "cable through a river" problem, instead of trying to be "current"

    anyway...

    Make a sketch labeling his position B and the point on the road 32 km away as A. let the point 16 km down from A be C
    Suppose he aims for a point on the road between A and C, call that P, let AP=x
    So his path is BP +PC
    then BP^2 = x^2 + 32^2
    BP = (x^2 + 1024)^(1/2)
    time to go BP = (x^2 + 1024)^(1/2)/48
    time to go PC = (16-x)/80

    T = (x^2+1024)^(1/2) /48+ 16/80 - x/80
    dT/dx = (1/96)(x^2 + 1024)^(-1/2) (2x) - 1/80
    = 0 for a min of T
    2x/(96√(x^2+1024)) = 1/80
    96√(x^2+1024) = 160x
    3√(x^2+1024) = 5x
    square both sides
    9(x^2 + 1024) = 25x^2
    9216 = 16x^2
    x^2 = 576
    x = √576 = 24

    But we clearly expected x to be between 0 and 16, so let's investigate the two direct routes.
    1. directly to A, then AP
    T = 32/48 + 16/80 = .86666 hrs
    2. directly to C
    distance = √(16^2 + 32^2) = √1280
    T = √1280/48 = .7454

    3. If we "blindly" sub in our x = 24 we get a total time
    of T = √1600/48 + (-8/80) = 11/15 = .73333

    3. consider a point between A and C, say x = 4
    distance through sand = √(32^2+4^2) = √1040
    time through sand = √1040/48 = .67185 hrs
    time along road = 12/80 = .15
    total time = .82185

    I am puzzles by these results, and I can only guess that I made some arithmetic error somewhere. Just can't seem to find it, perhaps somebody else can find it.

    anyway , he has 50 minutes to get there.
    my 3 answers are :
    .866666.. hrs = 52 minutes , go boom!
    .7454 hrs = 44.7 minutes, that would do it
    .7333333.. hrs = 44 minutes, so would that.

  • Calc - ,

    let me take a whack at it.
    If the jeep arrives at the road a distance x from the bomb, then

    the distance on road is x
    distance on sand is √(32^2 + (16-x)^2)

    travel time is thus

    t = x/80 + √(32^2 + (16-x)^2)/48
    dt/dx = 1/80 - (16-x)/48√(x^2-32x+1280)

    dt/dx = 0 when x = -8
    Also puzzling. And the graph of t(x) appears not to have a minimum for x>0.

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