Posted by **Kevin** on Saturday, October 20, 2012 at 7:27pm.

solve log(7x-3)+2log(5)=2+log(x+3)

I've attempted to do this question and I ended up with log(7-3)+log(5^2)-log(x+3)=2 but I don't what to do next or whether I did something wrong.

- Math -
**Reiny**, Sunday, October 21, 2012 at 12:18am
write is as

log((7x-3)(25)/(x+3) = 2

25(7x - 3)/(x+3) = 10^2 = 100

divide by 25

(7x-3)(x+3) = 4

cross-multiply

7x-3 = 4x+12

3x = 15

x = 5

check:

LS = log 32 + log 25 - log 8

= log(32(25)/8)

= log 100

= 2

= RS

- Math -
**Kevin**, Sunday, October 21, 2012 at 1:31pm
Just wondering what did you do in this log((7x-3)(25)/(x+3) = 2 to get 25(7x - 3)/(x+3) = 10^2 = 100?

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