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Posted by on Saturday, October 20, 2012 at 4:41pm.

The most prominent line in the atomic spectrum of mercury occurs at a wavelength of 253.652 nm. What is the energy of 0.625 moles of photons associated with the most prominent line? Express answer in kJ.

ANS:
295 kJ

Please explain.. Thank you so much!

  • chem need help - , Saturday, October 20, 2012 at 4:47pm

    E = hc/wavelength
    Solve for E. Wavelength must be in m and c in m/s. E is in joules/photon; therefore, multiply by 6.02E23 to convet to a mole of photons and multiply that by 0.625 for 0.625 mols photons. The answer is in joules.

  • chem need help - , Sunday, October 21, 2012 at 11:07am

    Got it, thank youu!

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