The most prominent line in the atomic spectrum of mercury occurs at a wavelength of 253.652 nm. What is the energy of 0.625 moles of photons associated with the most prominent line? Express answer in kJ.
Please explain.. Thank you so much!
chem need help - DrBob222, Saturday, October 20, 2012 at 4:47pm
E = hc/wavelength
Solve for E. Wavelength must be in m and c in m/s. E is in joules/photon; therefore, multiply by 6.02E23 to convet to a mole of photons and multiply that by 0.625 for 0.625 mols photons. The answer is in joules.
chem need help - Kjd, Sunday, October 21, 2012 at 11:07am
Got it, thank youu!