Posted by **Candice** on Saturday, October 20, 2012 at 9:18am.

A particle is projected horizontally with velocity V m/s, from a point h meters above ground. Taking g ms^-2 as the acceleration due to gravity,

1. Show the equation of the path is given by y = (2hV^2 - gx^2)/ 2V^2

2. Find the range of the particle.

Thanks

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