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physics

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After you pick up a spare, your bowling ball rolls without slipping back toward the ball rack with a linear speed of v = 3.27 m/s


To reach the rack, the ball rolls up a ramp that rises through a vertical distance of h = 0.572 m. What is the linear speed of the ball when it reaches the top of the ramp?

  • physics - ,

    KE=PE
    KE= KE(transl) +KE(rot) =
    =m•v²/2+Iω²/2=
    = m•v²/2+ (2mR²)• v²/5•2•R²=
    = m•v²/2+ mv²/5 =0.7 mv²

    0.7•m•v²=mgh
    v=sqrt(g•h/0.7)

  • physics - ,

    That is exactly the way I have been doing this problem and I keep getting the wrong answer. I keep getting 2.831 m/s

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