Posted by **Emily** on Friday, October 19, 2012 at 11:55pm.

After you pick up a spare, your bowling ball rolls without slipping back toward the ball rack with a linear speed of v = 3.27 m/s

To reach the rack, the ball rolls up a ramp that rises through a vertical distance of h = 0.572 m. What is the linear speed of the ball when it reaches the top of the ramp?

- physics -
**Elena**, Saturday, October 20, 2012 at 6:16am
KE=PE

KE= KE(transl) +KE(rot) =

=m•v²/2+Iω²/2=

= m•v²/2+ (2mR²)• v²/5•2•R²=

= m•v²/2+ mv²/5 =0.7 mv²

0.7•m•v²=mgh

v=sqrt(g•h/0.7)

- physics -
**Emily**, Sunday, October 21, 2012 at 10:09pm
That is exactly the way I have been doing this problem and I keep getting the wrong answer. I keep getting 2.831 m/s

## Answer this Question

## Related Questions

- Physics - After you pick up a spare, your bowling ball rolls without slipping ...
- physics - A spherical bowling ball with mass m = 4.1 kg and radius R = 0.116 m ...
- Physics - A bowling ball of mass M and radius R is thrown along a level surface ...
- Physics - A bowling ball of mass M and radius R is thrown along a level surface ...
- Physics - A ball of radius 0.300 m rolls along a horizontal table top with a ...
- Physics - A bowling ball encounters a 0.760-m vertical rise on the way back to ...
- Physics - A bowling ball encounters a 0.760 m vertical rise on the way back to ...
- physics - A bowling ball encounters a 0.760-m vertical rise on the way back to ...
- Physics - A spherical bowling ball with mass m = 3.2 kg and radius R = 0.107 m ...
- Physics - A uniform, spherical bowling ball of mass m and radius R is projected ...