What equation illustrates the relationship between the electric field strength and the potential difference?
E = d / v
E = v / d
d = E(v)
E = v(d)
I'm honestly clueless on this one
E = v / d
To understand the relationship between electric field strength and potential difference, we can start by defining these two terms.
The electric field strength (E) represents the force experienced by a positive test charge placed in an electric field. It is defined as the force per unit positive charge.
The potential difference (V), also known as voltage, represents the amount of work done in moving a unit positive charge between two points in an electric field. It is measured in volts (V).
Now, let's understand the relationship between these two quantities through the concept of electric potential.
The electric potential (V) at a point in an electric field is the electric potential energy per unit positive charge at that point. Mathematically, it is given by:
V = U / q
Where V is the potential (in volts), U is the electric potential energy (in joules), and q is the charge (in coulombs).
Now, the electric field strength (E) is related to the potential difference (V) by the following equation:
E = - dV / dx
Where E is the electric field strength (in N/C), dV is the change in potential (in volts), and dx is the displacement along the field (in meters).
Therefore, the correct equation illustrating the relationship between the electric field strength (E) and the potential difference (V) is:
E = - dV / dx
It is important to note that the negative sign indicates that the electric field is directed from higher potential to lower potential.