A metal sphere has a charge of -6 µC. How many excess electrons are there on the sphere?
4x10^-13
10x10^13
4x10^13
10x10^-13
I'm stuck between A or D...
N=q/e =6•10⁻⁶/1.6•10⁻¹⁹=3.75•10¹³=4•10¹³
To determine the number of excess electrons on the metal sphere with a charge of -6 µC, we can use the equation:
Q = Ne
Where Q is the charge, N is the number of excess electrons, and e is the elementary charge.
Given that the charge is -6 µC (microcoulombs) and the elementary charge is 1.6 x 10^-19 C (coulombs), we can calculate the number of excess electrons:
N = Q / e
Plugging in the values:
N = (-6 x 10^-6 C) / (1.6 x 10^-19 C)
Simplifying:
N = -3.75 x 10^13
Therefore, there are approximately 3.75 x 10^13 excess electrons on the metal sphere with a charge of -6 µC.
In the given options, option D states "10x10^-13", which is incorrect based on the calculation. The correct answer is option A, "4x10^-13".
To determine the number of excess electrons on the metal sphere, we need to use the elementary charge, which is the charge of a single electron or proton. The elementary charge is approximately 1.6 x 10^-19 coulombs (C).
We can calculate the number of excess electrons using the formula:
Number of excess electrons = Charge / Elementary charge
Plugging in the values, we have:
Number of excess electrons = (-6 x 10^-6 C) / (1.6 x 10^-19 C)
Simplifying, we get:
Number of excess electrons = -6 x 10^-6 / 1.6 x 10^-19
Dividing the values, we have:
Number of excess electrons ≈ -3.75 x 10^13
Since the question is asking for the number of excess electrons, which should be a positive value, we can conclude that the correct answer is:
10 x 10^13
Therefore, the answer is B.