Three blocks are in contact with each other

on a frictionless horizontal surface. A 696 N
horizontal force is applied to the block with
mass of 4.7 kg as shown in the figure below.
The acceleration of gravity is 9.8 m/s
2
.
4.7 kg 5.5 kg 7.1 kg

d) What is the magnitude of the force between
the block with mass 5.5 kg and 7.1 kg?

To find the magnitude of the force between the block with mass 5.5 kg and 7.1 kg, you need to consider Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. In this case, the force between the block with mass 5.5 kg and 7.1 kg is the reaction force to the applied force on the block with mass 4.7 kg. Therefore, the magnitude of the force between the two blocks is equal to the magnitude of the applied force.

Since the applied force on the block with mass 4.7 kg is given as 696 N, the magnitude of the force between the block with mass 5.5 kg and 7.1 kg is also 696 N.