Question

what is the integral of (e^x)/(sqrt(9(e^2x))-25)?

Answer 1

sqrt(9(e^2x)) = 3e^x and you have

e^x/(3e^x - 25) dx
let u = 3e^x-25, so du = 3e^x dx and you have
integral 1/3 du/u = 1/3 log (3e^x - 25)