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April 18, 2014

April 18, 2014

Posted by **Anonymous** on Thursday, October 18, 2012 at 4:58pm.

The area of triangle XYZ is 12cm^2. The |<PQR|= 30 degrees, 150 degrees.

Find the two possible |XZ|

- math - eh? -
**Steve**, Thursday, October 18, 2012 at 5:18pmGiven XYZ, WTF is PQR?

- Math -
**Anonymous**, Thursday, October 18, 2012 at 5:22pmI mean |<XYZ|

- Math -
**Anonymous**, Thursday, October 18, 2012 at 5:22pmI mean |<XYZ|

- Math -
**Steve**, Friday, October 19, 2012 at 4:37amXZ^2 = 6^2 + 8^2 - 2*6*8cosY

cosY is either sqrt(3)/2 or -sqrt(3)/2

XZ^2 = 100-96*.866

XZ = 4.1

or

XZ^2 = 100+96*.866

XZ = 13.5

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