Homework Help: Physics

Posted by Karrine on Thursday, October 18, 2012 at 12:48pm.

A race car starts from rest on a circular track of radius 500 m. The car's speed increases at the constant rate of 0.520 m/s2. At the point where the magnitudes of the centripetal and tangential accelerations are equal, find the following.
a)speed of the race car (m/s)
b)the distance traveled (m)
c)elapsed time (s)

The answer that is on the other questions asked is wrong...please help!

Physics - Elena, Thursday, October 18, 2012 at 1:45pm
a(τ)=0.52 m/s², R=500 m
v=? s=? t=?
------
v=a(τ) •t
centripetal (normal) acceleration is
a(n)=v²/R =( a(τ) •t)²/R = a(τ),
a(τ) ² •t²/R = a(τ),
t=sqrt{R/a(τ)}=sqrt{500/0.52)= 31 s,
s=a(τ) •t²/2 = 0.52•31²/2 =249.9 m,
v= a(τ) •t =0.52•31 = 16.12 m/s.

Answer this Question

Related Questions

Physics - A race car starts from rest on a circular track of radius 445 m. The ...
physics - A race car starts from rest on a circular track. The car increases its...
physics - A toy race car starts from rest on a circular track of radius 4.30 m. ...
physics - A toy race car starts from rest on a circular track of radius 4.30 m. ...
Math - A race car starts from rest on a circular track of radius 565 m. The car...
Physics - A race car starts from rest on a circular track of radius 507 m. The ...
PHYSICS - super easy (I think) but I must be missing some concept... A race car ...
Physics HELP! - A toy race car starts from rest on a circular track of radius 4....
Physics- PLEASE HELP - A toy race car starts from rest on a circular track of ...
physics - A race car starts from rest on a circular track of radius 265 m. The ...

For Further Reading

First Name:
School Subject:
Answer: