Posted by **Karrine** on Thursday, October 18, 2012 at 12:48pm.

A race car starts from rest on a circular track of radius 500 m. The car's speed increases at the constant rate of 0.520 m/s2. At the point where the magnitudes of the centripetal and tangential accelerations are equal, find the following.

a)speed of the race car (m/s)

b)the distance traveled (m)

c)elapsed time (s)

The answer that is on the other questions asked is wrong...please help!

- Physics -
**Elena**, Thursday, October 18, 2012 at 1:45pm
a(τ)=0.52 m/s², R=500 m

v=? s=? t=?

------

v=a(τ) •t

centripetal (normal) acceleration is

a(n)=v²/R =( a(τ) •t)²/R = a(τ),

a(τ) ² •t²/R = a(τ),

t=sqrt{R/a(τ)}=sqrt{500/0.52)= 31 s,

s=a(τ) •t²/2 = 0.52•31²/2 =249.9 m,

v= a(τ) •t =0.52•31 = 16.12 m/s.

## Answer this Question

## Related Questions

- Math - A race car starts from rest on a circular track of radius 565 m. The car'...
- physics - A toy race car starts from rest on a circular track of radius 4.30 m. ...
- physics - A toy race car starts from rest on a circular track of radius 4.30 m. ...
- Physics - A race car starts from rest on a circular track of radius 445 m. The ...
- Physics HELP! - A toy race car starts from rest on a circular track of radius 4....
- physics - A race car starts from rest on a circular track of radius 265 m. The ...
- Physics- PLEASE HELP - A toy race car starts from rest on a circular track of ...
- Physics - A race car starts from rest on a circular track of radius 507 m. The ...
- physics - a race car starts from rest on a circular track.the car increases its ...
- physics - A race car starts from rest on a circular track. The car increases its...