Posted by Phillip on Thursday, October 18, 2012 at 12:28pm.
y = √(x^(1/x)) = x^(1/2x)
ln y = 1/(2x) ln x
1/y y' = -1/(2x^2) lnx + 1/(2x)(1/x)
1/y y' = (1-lnx)/(2x^2)
y' = (1-lnx)y/(2x^2)
= (1-lnx) √(x^(1/x))/(2x^2)
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