Posted by **Greg** on Thursday, October 18, 2012 at 9:21am.

Find the critical points of f(x)=x^4e^-x.

You would use the product rule.

Then what?

- Calculus -
**Reiny**, Thursday, October 18, 2012 at 9:40am
set the derivative equal to zero and solve for x

plug those x values back into the original equation to find the critical points

- Calculus -
**Greg**, Thursday, October 18, 2012 at 10:15am
Would the derivative be e^-x (x^4-4x^3)?

- Calculus -
**Steve**, Thursday, October 18, 2012 at 10:25am
almost.

d/dx(e^-x) = -e^-x

so,

df/dx = (4x^3)(e^-x) + (x^4)(-e^-x)

= e^-x (4x^3 - x^4)

= x^3 e^-x (4-x)

set that to zero, which occurs at x=4

luckily, in this case, you would still have gotten the correct answer, since the only mistake was the sign of df/dx.

- Calculus -
**Reiny**, Thursday, October 18, 2012 at 10:30am
dy/dx= x^4(e^-x)(-1) + e^-x (4x^3)

= e^-x( -x^4 - 4x^3)

(looks like you forgot the derivative of the exponent -x )

to solve:

e^-x = 0 or -x^4 - 4x^3 = 0

e^-x = 0 has no solution

x^4 + 4x^3 = 0

x^3(x+4) = 0

x = 0 or x = -4

now sub back in

- Calculus -
**Greg**, Thursday, October 18, 2012 at 10:46am
Sub 0 and -4 into f(x). or f'(x)?

- Calculus -
**Greg**, Thursday, October 18, 2012 at 10:57am
f(x)=x^4e^-x

f(0)=0^4e^0 = 0

f(-4)=-4^4e^4 = 13977.13

I feel like i didnt do that right. It seems like a weird number for a critcal point.

- Calculus -
**Steve**, Thursday, October 18, 2012 at 11:01am
must be because the value for x is 4, not -4

- Calculus -
**Greg**, Thursday, October 18, 2012 at 11:05am
f(4)= 4^4 e^-4 = 4.6888

## Answer this Question

## Related Questions

- calculus - Use a graph of f(x) = 3 e^{-8 x^2} to estimate the x-values of any ...
- Calculus - How do I use the chain rule to find the derivative of square root(1-x...
- Calculus - y= [(x-3)/(x^2+1)]^2 I know that I would use the product rule on the ...
- Calculus - This is a calculus homework question but in reality the problem here ...
- Pre-Calculus - Find dy/dx if y= x^6[(x^2-9)^8]? So the answer is supposed to be ...
- Calculus/Derivatives - In addition, can you walk me through how to get the ...
- CALCULUS - Use the product rule to calculate the derivative. dh dx x = 4 , h (x...
- Calculus - g(x)=[(4x-7)(x+11)] Find g'(x) I thought that you use the product ...
- calculus - f(x)= - 2x^3 + 45x^2 -300x +9 There are 3 intervals (-inf,A], [A,B...
- calculus - how do not understand how to find a deriviative of this function?Do i...