Monday

July 28, 2014

July 28, 2014

Posted by **Anonymous** on Wednesday, October 17, 2012 at 9:33pm.

- Trig -
**Steve**, Wednesday, October 17, 2012 at 11:37pmLet the height of the building be h; let the man start at distance x from the building.

(h-5)/x = tan40 = 0.839

(h-5)/(x-100) = tan60 = 1.732

h = 167.7 ft

x = 193.9 ft

check:

162.7/193.9 = 0.839

162.7/93.9 = 1.732

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