A 1.16 kg block and a 2.32 kg block are initially at rest on a frictionless, horizontal surface, with a compressed spring of negligible mass between them. When the blocks are released, they move off in opposite directions. If the final velocity of the 1.16 kg block is 3.20 m/s to the left, what is the final velocity of the 2.32 kg block?
a.) Find Magnitude
b.) How much does the kinetic energy of the system increase?
0=m1•v1+m2•v2
v2= - m1•v1/v2= - 1.16•3.2/2.32 =1.6 m/s.
KE1=0
KE2=m1•v1²/2 +m2•v2²/2 =...
ΔKE=KE2-KE1=KE2