Posted by Megan on Wednesday, October 17, 2012 at 3:43pm.
m₁=58 kg, v₁₀=4.2 m/s,
m₂= 0.45 kg, v₂₀= 26 m/s
v₂={ 2m₁v₁₀ - (m₂-m₁)v₂₀}/(m₁+m₂) =
={ 2•58•4.2 - (0.45-58) •26}/(58+0.45)=
=33.9 m/s.
F=m•Δv/t = m•(v₂-v₁)/t =58{33.9-(-26)}19•10⁻³=1.82•10⁵ N.
(b) If the ball is in contact with the players head for 19 ms, what is the average acceleration of the ball?
F=m2•a
I think the value I am getting is too large, what value are you getting?
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