# chemistry

posted by on .

calculate the morality of THE H2SO4 solution for each of the three runs. do the three values agree closely together with each other.
Part A.

Titration 1
volume of unknown acid =20ml
initial buret reading of NaOH =0.5 ml

Titartion 2
volume of unknown acid =20ml
final buret reading of NaOH = 36.0ml

titartion 3
volume of unknown acid 20ml
final buret reading of NaOH 25.ml

• chemistry - ,

Several things I should mention.
It's molarity, not morality. I don't know if these solution are moral or not. :-).
Second, you don't list a molarity of the NaOH. You must have that in order to calculate the molarity of the unknown acid.

mols NaOH = M(not listed) x L = ?

mols acid = same as mols NaOH
Then M acid = mols acid/L acid.

• chemistry - ,

THOSE ARE THE RESULT IN MY LAB AND I HAVE TO CALCULATE THE MOLARITY OF THE THREE TITRATIONS. HOW DO I FIND THE VALUES IN THE H2SO4

• chemistry - ,

My first response was in error where I said mols H2SO4 =same as mols NaOH. That isn't correct.
Here are the correct instructions.
H2SO4 + 2NaOH ==> 2H2O x Na2SO4

mols NaOH = M NaOH (M not listed in the post) x x L NaOH.

Convert to mols H2SO4.
mols H2SO4 = 1/2 x mols NaOH
Then M H2SO4 = mols H2SO4/L H2SO4.