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chemistry

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calculate the morality of THE H2SO4 solution for each of the three runs. do the three values agree closely together with each other.
Part A.

Titration 1
volume of unknown acid =20ml
initial buret reading of NaOH =0.5 ml
final buret reading of NaOH=10.0ml

Titartion 2
volume of unknown acid =20ml
initial buret reading of NaOH=18.0.ml
final buret reading of NaOH = 36.0ml

titartion 3
volume of unknown acid 20ml
intinal reading of NaOH =7.3
final buret reading of NaOH 25.ml

  • chemistry - ,

    Several things I should mention.
    It's molarity, not morality. I don't know if these solution are moral or not. :-).
    Second, you don't list a molarity of the NaOH. You must have that in order to calculate the molarity of the unknown acid.

    volume NaOH = final reading-initial reading.
    mols NaOH = M(not listed) x L = ?

    mols acid = same as mols NaOH
    Then M acid = mols acid/L acid.

  • chemistry - ,

    THOSE ARE THE RESULT IN MY LAB AND I HAVE TO CALCULATE THE MOLARITY OF THE THREE TITRATIONS. HOW DO I FIND THE VALUES IN THE H2SO4

  • chemistry - ,

    My first response was in error where I said mols H2SO4 =same as mols NaOH. That isn't correct.
    Here are the correct instructions.
    H2SO4 + 2NaOH ==> 2H2O x Na2SO4

    volume NaOH = final reading - initial reading.
    mols NaOH = M NaOH (M not listed in the post) x x L NaOH.

    Convert to mols H2SO4.
    mols H2SO4 = 1/2 x mols NaOH
    Then M H2SO4 = mols H2SO4/L H2SO4.

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