Posted by Megan on Wednesday, October 17, 2012 at 12:54pm.
m1=66.1 kg, v1=2.29 m/s
m2=0.046 kg, v2= 31.7 m/s
m3=60.5 kg, v3=0
u1=? u3=?
The law of conservation of linear momentum
(m1+m2) •v1 =m1•u1 +m2•v2
u1= [(m1+m2) •v1- m2•v2]/m1 =
=[(66.1+0.046) •2.29 – 0.046•31.7]/66.1 = 2.269 m/s
m2•v2=(m2+m3) •u3
u3= m2•v2/(m2+m3) =
=0.046•31.7/(0.046+60.5)=0.024 m/s
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