Posted by **Anthony** on Wednesday, October 17, 2012 at 12:25pm.

A Football is kicked 66.6 meters in 5.39 seconds. What was the initial velocity it was kicked?

magnitude and direction above horizontal

- PHYICS -
**Jennifer**, Wednesday, October 17, 2012 at 3:54pm
x = vx*t

y = vy*t - 0.5*9.8*t^2

Assuming it hits the ground at 5.39 seconds:

66 = vx*5.39

0 = vy * 5.39 - 0.5*9.8*5.39^2

Where vx is the speed in the x direction, vy is the speed in the y direction.

The magnitude of the speed is

(vx^2 + vy^2)^0.5

The direction of the speed is given by

tan(x) = vy / vx

Solve for the angle x

- PHYICS -
**Anthony**, Wednesday, October 17, 2012 at 5:16pm
how do you get the vy by it self when trying to get tionhe speed in the y direct

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