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A Football is kicked 66.6 meters in 5.39 seconds. What was the initial velocity it was kicked?
magnitude and direction above horizontal

  • PHYICS -

    x = vx*t
    y = vy*t - 0.5*9.8*t^2

    Assuming it hits the ground at 5.39 seconds:

    66 = vx*5.39
    0 = vy * 5.39 - 0.5*9.8*5.39^2

    Where vx is the speed in the x direction, vy is the speed in the y direction.

    The magnitude of the speed is

    (vx^2 + vy^2)^0.5

    The direction of the speed is given by

    tan(x) = vy / vx
    Solve for the angle x

  • PHYICS -

    how do you get the vy by it self when trying to get tionhe speed in the y direct

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