Posted by Anthony on .
A football is kicked 66.6 meters. If it is in the air for 5.39 seconds, with what initial velocity was it kicked?
magnitude and direction above horizontal

PHYICS NEED HELP BAD! 
Elena,
L=vₒ²•sin2α/g = 66.6
t= 2vₒ•sinα/g = 5.39
vₒ = t•g/2•sinα
L=vₒ²•sin2α/g= t²•g²•2•sinα•cosα/g•4•sin²α= t²•g/2•tanα
tanα = t²•g/2•L
α= arctan t²•g/2•L =
=arctan (5.39²•9.8/2•66.6)=64.9°.
vₒ = t•g/2•sinα=5.39•9.8/2•sin 64.9°=... 
PHYICS NEED HELP BAD! 
Anthony,
NEED HELP BAD

PHYICS NEED HELP BAD! 
Anthony,
IT IS NOT COMING OUT RIGHT