Posted by **Anthony** on Wednesday, October 17, 2012 at 11:11am.

A football is kicked 66.6 meters. If it is in the air for 5.39 seconds, with what initial velocity was it kicked?

magnitude and direction above horizontal

- PHYICS NEED HELP BAD! -
**Elena**, Wednesday, October 17, 2012 at 11:29am
L=vₒ²•sin2α/g = 66.6

t= 2vₒ•sinα/g = 5.39

vₒ = t•g/2•sinα

L=vₒ²•sin2α/g= t²•g²•2•sinα•cosα/g•4•sin²α= t²•g/2•tanα

tanα = t²•g/2•L

α= arctan t²•g/2•L =

=arctan (5.39²•9.8/2•66.6)=64.9°.

vₒ = t•g/2•sinα=5.39•9.8/2•sin 64.9°=...

- PHYICS NEED HELP BAD! -
**Anthony**, Wednesday, October 17, 2012 at 11:50am
NEED HELP BAD

- PHYICS NEED HELP BAD! -
**Anthony**, Wednesday, October 17, 2012 at 11:55am
IT IS NOT COMING OUT RIGHT

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