PHYICS NEED HELP BAD!
posted by Anthony on .
A football is kicked 66.6 meters. If it is in the air for 5.39 seconds, with what initial velocity was it kicked?
magnitude and direction above horizontal

L=vₒ²•sin2α/g = 66.6
t= 2vₒ•sinα/g = 5.39
vₒ = t•g/2•sinα
L=vₒ²•sin2α/g= t²•g²•2•sinα•cosα/g•4•sin²α= t²•g/2•tanα
tanα = t²•g/2•L
α= arctan t²•g/2•L =
=arctan (5.39²•9.8/2•66.6)=64.9°.
vₒ = t•g/2•sinα=5.39•9.8/2•sin 64.9°=... 
NEED HELP BAD

IT IS NOT COMING OUT RIGHT