Posted by Anthony on Wednesday, October 17, 2012 at 11:11am.
A football is kicked 66.6 meters. If it is in the air for 5.39 seconds, with what initial velocity was it kicked?
magnitude and direction above horizontal

PHYICS NEED HELP BAD!  Elena, Wednesday, October 17, 2012 at 11:29am
L=vₒ²•sin2α/g = 66.6
t= 2vₒ•sinα/g = 5.39
vₒ = t•g/2•sinα
L=vₒ²•sin2α/g= t²•g²•2•sinα•cosα/g•4•sin²α= t²•g/2•tanα
tanα = t²•g/2•L
α= arctan t²•g/2•L =
=arctan (5.39²•9.8/2•66.6)=64.9°.
vₒ = t•g/2•sinα=5.39•9.8/2•sin 64.9°=...

PHYICS NEED HELP BAD!  Anthony, Wednesday, October 17, 2012 at 11:50am
NEED HELP BAD

PHYICS NEED HELP BAD!  Anthony, Wednesday, October 17, 2012 at 11:55am
IT IS NOT COMING OUT RIGHT
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