posted by Renka Jai on .
How many newtons of force are necessary to accelerate a 0.0050 kg mass at the acceleration (a) of 9.81 m/s2 with the force expressed in the correct number of significant figures? (F = ma)
4.91 × 102 N
Please help me :( It's just one little question.
9.81 has three sig figs.
.0050 is two figs, the 50 on the end
.0050 * 9.981 = .04905
which to two sig figs is .049 N