Homework Help: chemistry

Posted by shahab on Wednesday, October 17, 2012 at 1:38am.

c. A student put 1.18 mole of substance A and and 2.85 mole of substance B into a 10 litre flask which was then closed. The reaction that took place was: A(g)+ 2B(g) 3C(g) + D(g)
On analysis the equilibrium mixture at 25 0 C was found to contain 0.376mole of D. Calculate Kc and Kp at this temperature.

[ R = 0.0821atm l mole-1K-1].

chemistry - DrBob222, Wednesday, October 17, 2012 at 3:35pm
These are in 1 L; therefore, mols = M.
........A + 2B ==> 3C + D
I .....1.18..2.85...0....0
C......-x....-2x...3x....x
E...1.18-x..2.85-x..3x...x
x in the problem = 0.376 for D at equilibrium.
Calculate concns of each of the others and substitute into Keq expression and solve for Kc.
Then convert top Kp = Kc*RT^{delta n}

Answer this Question

Related Questions

Chemistry - For the equation: deltaHrxn = qrxn / mol substance to calculate ...
Chemistry(Please help, thank you) - For the equation: deltaHrxn = qrxn / mol ...
Chemistry (Check) - Completion 1) 2)6.02 X 1023 Chemists relate units of ...
chemistry - Which of the following is true of a substance with a pH of 11.0? A. ...
Chemistry - Select the two conditions that must be met by a thermochemical ...
chemistry - Substance A and substance B react to form substance C as described ...
Chemistry - Suppose 1.0 mol of substance A reacts with 1.0 mol of substance B. ...
chemistry - substance X has a molar mass of 107.6 g/mol. When 2.50 g of ...
Chemistry - The term mole is used in chemistry to define an amount of a ...
chemistry - An unknown substance has a mass of 17.3 . When the substance ...

For Further Reading

First Name:
School Subject:
Answer: