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April 16, 2014

April 16, 2014

Posted by **Anonymous** on Tuesday, October 16, 2012 at 11:03pm.

tan(sin−1x)=

- math -
**Anonymous**, Tuesday, October 16, 2012 at 11:04pmsorry I meant tan(sin^-1 x)=

- math -
**Reiny**, Wednesday, October 17, 2012 at 8:41amsin^-1 x is angle in a right - angled triangle where the opposite side is x and the hypotenuse is 1

let that angle be Ø

so really sin^-1 x ----> sinØ = x/1

so the third side is √(1 - x^2)

then tan(sin^-1 x)

= tan Ø**= x/√(1-x^2)**

check:

e.g. let x = .5

then sin^-1 (.5) = π/6

and tan(π/6) = .57735

according to my answer

tan(sin^-1 (.5)) = .5/√(1-.25) = .57735

all looks good.

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