Posted by Anonymous on Tuesday, October 16, 2012 at 11:03pm.
Rewrite the expression as an algebraic expresion in x:
- math - Anonymous, Tuesday, October 16, 2012 at 11:04pm
sorry I meant tan(sin^-1 x)=
- math - Reiny, Wednesday, October 17, 2012 at 8:41am
sin^-1 x is angle in a right - angled triangle where the opposite side is x and the hypotenuse is 1
let that angle be Ų
so really sin^-1 x ----> sinŲ = x/1
so the third side is √(1 - x^2)
then tan(sin^-1 x)
= tan Ų
e.g. let x = .5
then sin^-1 (.5) = π/6
and tan(π/6) = .57735
according to my answer
tan(sin^-1 (.5)) = .5/√(1-.25) = .57735
all looks good.
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