Posted by josh on .
the turning point for y= x^28x+2 is:
A (2,16)
B (16,2)
C (8,2)
D (8,2)
E (4,14)

math 
Steve,
you can rewrite it as
y = x^28x+16 + 216
y = (x4)^2  14
Now it should be clear where the turning point (vertex) is.