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the turning point for y= x^2-8x+2 is:

A (2,-16)
B (16,2)
C (8,-2)
D (-8,2)
E (4,-14)

  • math -

    you can rewrite it as

    y = x^2-8x+16 + 2-16
    y = (x-4)^2 - 14

    Now it should be clear where the turning point (vertex) is.

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