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posted by josh on Tuesday, October 16, 2012 at 9:25pm.
the turning point for y= x^2-8x+2 is: A (2,-16) B (16,2) C (8,-2) D (-8,2) E (4,-14)
you can rewrite it as y = x^2-8x+16 + 2-16 y = (x-4)^2 - 14 Now it should be clear where the turning point (vertex) is.
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