Karl Malone made 474 out of 621 free throws attempts and John Stockton made 237 out of 287 free throws attempts.

a. what fraction benchmark is near the number of free throws made by each player?
b. Estimate the percent of free throws made by each player.

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idk i need help too! with the same question! ughh

A. 5/6 is the fraction

75% and 85%

To answer these questions, we need to find the fraction benchmark and estimate the percent of free throws made by each player.


a. The fraction benchmark is a fraction that is close to the actual value but has easy-to-work-with denominators. To find the fraction benchmark for each player, we need to simplify the fractions.

For Karl Malone:
Free throws made = 474
Free throw attempts = 621

To simplify this fraction, we can divide both the numerator and denominator by their greatest common divisor (GCD). In this case, the GCD of 474 and 621 is 3.

Simplifying 474/621:
474 ÷ 3 = 158
621 ÷ 3 = 207

So, the fraction benchmark for Karl Malone is 158/207.

For John Stockton:
Free throws made = 237
Free throw attempts = 287

Similarly, we divide both the numerator and denominator by their GCD, which in this case is 1 (since 237 and 287 are already relatively prime).

So, the fraction benchmark for John Stockton is simply 237/287.

b. To estimate the percent of free throws made by each player, we can convert the fraction benchmark to a decimal and then multiply by 100 to get the percentage.

For Karl Malone:
Fraction benchmark = 158/207
Decimal value = 158 ÷ 207 ≈ 0.7623 (rounded to four decimal places)
Percentage = 0.7623 × 100 ≈ 76.23% (rounded to two decimal places)

So, the estimated percent of free throws made by Karl Malone is approximately 76.23%.

For John Stockton:
Fraction benchmark = 237/287
Decimal value = 237 ÷ 287 ≈ 0.8246 (rounded to four decimal places)
Percentage = 0.8246 × 100 ≈ 82.46% (rounded to two decimal places)

Thus, the estimated percent of free throws made by John Stockton is approximately 82.46%.