Posted by **Anonymous** on Tuesday, October 16, 2012 at 8:37pm.

y = 1/2x^2-x + 3 for 0_<x_<6.

(b) Calculate the mid-ordinates of 5 strips between x = 1 and x = 6, and hence use the mid- ordinate rule to approximate the area under between x = 1, x = 6 and the x-axis.

(c) Assuming that the area determined by integration to be the actual area, calculate the percentage error in using the mid-ordinate rule.

## Answer this Question

## Related Questions

- Math - y = ½ x^2 – x +3 for 1≤x≤6 (b) Calculate the mid- ordinates ...
- math - y = ½ x^2 – x +3 for 0≤x≤6 (b) Calculate the mid- ordinates ...
- Math - Graph y = ½ x^2 – x +3 for 0≤x≤6 Calculate the mid- ordinates...
- math - Graph y = ½ x^2 – x +3 for 0≤x≤6 (b) Calculate the mid- ...
- math - Graph y = ½ x^2 – x +3 for 0≤x≤6 (b) Calculate the mid- ...
- Calculus - Estimate the area under the graph f(x)=3x^3 + 5 from x=-1 to x=5 ...
- bus. calc - Use the rectangle (mid-point) rule, with n=3 to approximate the ...
- Geometry - D is the mid-point of side AB of the triangle ABC, E is mid-point of ...
- calculus - The population of less-developed countries in mid-2007 of 4086 ...
- analytical geometry - two edges PQ,RS of a tetrahedron PQRS are perpendicular,...

More Related Questions