Posted by Neil on Tuesday, October 16, 2012 at 8:33pm.
The law of conservation of linear momentum for the inelastic collision
x: m1v1=(m1+m2) v cos30°
y: m2v2=(m1+m2) v sin30°
v1=2v cos30°
v2=2v sin30°
(m1+m2) a=F(fr)
a= F(fr)/(m1+m2)=F(fr)/2m=10000/2500=10m/s²
s=v²/2a =>
v=sqrt(2as)=sqrt (2103)=7.75 m/s.
v1=2v cos30°=27.75 cos30°=13.42 m/s
v2= 2v sin30°=27.75 sin30°=7.75 m/s
Related Questions
physics - Two vehicles with the same mass collide and lock together traveling 28...
physics - Two vehicles with the same mass collide and lock together traveling 28...
physics - Two cars approach an ice-covered intersection. One car, of mass 1.22 ...
Physics - Momentum of cars at intersection - Two cars of identical mass are ...
physics - Two automobiles of equal mass approach an intersection. One vehicle is...
physics - A 59.0-kg skater is traveling due east at a speed of 1.80 m/s. A 61.0-...
physics - A 56.0-kg skater is traveling due east at a speed of 2.80 m/s. A 77.0-...
Physics - Suppose two blocks of ice are heading toward each other. block A has ...
physics - One glider with a mass 0.2 kg and a speed of 3.5 m/s traveling east ...
math - Suppose two blocks of ice are heading toward each other. block A has a ...
For Further Reading