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February 28, 2015

February 28, 2015

Posted by **Neil** on Tuesday, October 16, 2012 at 8:33pm.

- Physics -
**Elena**, Wednesday, October 17, 2012 at 5:15amThe law of conservation of linear momentum for the inelastic collision

x: m1v1=(m1+m2) v cos30°

y: m2v2=(m1+m2) v sin30°

v1=2v cos30°

v2=2v sin30°

(m1+m2) a=F(fr)

a= F(fr)/(m1+m2)=F(fr)/2m=10000/2500=10m/s²

s=v²/2a =>

v=sqrt(2as)=sqrt (2103)=7.75 m/s.

v1=2v cos30°=27.75 cos30°=13.42 m/s

v2= 2v sin30°=27.75 sin30°=7.75 m/s

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