Friday

March 27, 2015

March 27, 2015

Posted by **Neil** on Tuesday, October 16, 2012 at 8:33pm.

- Physics -
**Elena**, Wednesday, October 17, 2012 at 5:15amThe law of conservation of linear momentum for the inelastic collision

x: m1v1=(m1+m2) v cos30°

y: m2v2=(m1+m2) v sin30°

v1=2v cos30°

v2=2v sin30°

(m1+m2) a=F(fr)

a= F(fr)/(m1+m2)=F(fr)/2m=10000/2500=10m/s²

s=v²/2a =>

v=sqrt(2as)=sqrt (2103)=7.75 m/s.

v1=2v cos30°=27.75 cos30°=13.42 m/s

v2= 2v sin30°=27.75 sin30°=7.75 m/s

**Answer this Question**

**Related Questions**

Physics - A 1800 kg mass car is traveling south at a velocity of 15 m/s through ...

physics - Two vehicles with the same mass collide and lock together traveling 28...

physics - Two vehicles with the same mass collide and lock together traveling 28...

physics - A 59.0-kg skater is traveling due east at a speed of 1.80 m/s. A 61.0-...

physics - A 56.0-kg skater is traveling due east at a speed of 2.80 m/s. A 77.0-...

Physics 141 - A 45.0-kg skater is traveling due east at a speed of 2.85 m/s. A ...

physics - A 51.5-kg skater is traveling due east at a speed of 2.70 m/s. A 69.5-...

Physics - Momentum of cars at intersection - Two cars of identical mass are ...

Physics - A 49.5-kg skater is traveling due east at a speed of 2.88 m/s. A 72.5-...

Physics - Am I correct? Two carts have a compressed spring between them and are ...