Posted by smiley on Tuesday, October 16, 2012 at 8:10pm.
k=2.75•10¹º A/m⁴ R=0.003 m
i=∫JdA=∫k•r²•2•π•r•dr= k•π•R²/2 =3.5 A
The rate of thermal energy generation is P=i•V=3.5•60=210 W.
Assuming a steady rate, the thermal energy generated in 2h=7200 s is
Q=P •Δt=210•7200= 1.5112 •10⁶ J
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