Posted by Anonymous on .
two trains leave Kansas City at the same time. Train A is traveling due north at 55 mph, train B is traveling west at the rate of 65 mph. Find the distance between the two trains two hours later and the bearing of train B from train A.
65*2 to get the west and 55*2 to get the north. 2 is from the hours, to solve the distance you must use Sin130^o = 110^o/d or distance. then the answer will be the distance then to find bearing just use Tan theta (represents the bearing) = 100^o/65^o. and that's how you get the bearing the answer must be N bearing W.
sorry if I'm wrong and I also appologizing for my grammar. I'm just 8 years old kid and I need to enchance my english ability :D