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How do you prepare a solution of 12 M HCl and want to prepare 500 mL of a 0.4 M solution. Assume you have a 500-mL volumetric flask

  • chem - ,

    I don't think your question is worded properly. I think you have 12 M HCl and want to prepare 500 mL of 0.4M.
    c1v1 = c2v2
    12*mL = 0.4*500
    Solve for mL of the 12 M material. Place that in the 500 mL volumetric flask and make to the mark. Shake thoroughly.

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