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March 26, 2017

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In a Broadway performance, an 80 kg actor swings from a 3.75 m long cable that is horizontal when he starts.?
At the bottom of his arc, he picks up his 55.0 kg costar in an inelastic collision. What maximum height do they reach after their upward swing?

  • physics - ,

    (a)

    PE=mgh=mgL
    KE = mv²/2
    Law of conservation of energy
    PE =KE
    mgL= mv²/2
    v=sqrt(2gL)=...
    (b) Law of conservation of linear momentum
    mv= (m+m1)u
    u= m•v/(m+m1)=...
    (c)
    Law of conservation of energy
    KE1=PE1
    (m+m1) •u²/2 =(m+m1) •g•h1
    h1=(m+m1) •u²/2 • (m+m1) •g =...

  • physics - ,

    KE1=PE1
    in the end should actually be...
    h1=(m+m1)(u^2)/2*g*(m+m1)
    where the sum of the masses cancel and you're left with: (u^2)/2*g

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