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March 29, 2017

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In a Broadway performance an 80.0 kg actor swings from a 2.05 m long cable that is horizontal when he starts. At the bottom of his arc he picks up his 47.0 kg costar in an inelastic collision. (a) What is the velocity of the swinging actor just before picking up the costar? (b) What is the velocity of both actors just after picking up the costar? (c) What maximum height do they reach after their upward swing?

  • Physics- Elena please help! - ,

    (a)

    PE=mgh=mgL
    KE = mv²/2
    Law of conservation of energy
    PE =KE
    mgL= mv²/2
    v=sqrt(2gL0=sqrt(2•9.8•2.05)=6.34 m/s.
    (b) Law of conservation og linear momentum
    mv= (m+m1)u
    u= m•v/(m+m1)=80•6.34/(80+47)=4 m/s
    (c)
    Law of conservation of energy
    KE1=PE1
    (m+m1) •u²/2 =(m+m1) •g•h1
    h1=(m+m1) •u²/2 • (m+m1) •g =...

  • Physics- Elena please help! - ,

    I'm still confused on part c.

  • Physics- Elena please help! - ,

    h1=(m+m1) •u²/2 • (m+m1) •g =u²/2 •g=
    =4²/2•9.8=0.82 m

  • Physics- Elena please help! - ,

    Thank you!

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