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September 23, 2014

September 23, 2014

Posted by **Laytin** on Tuesday, October 16, 2012 at 9:56am.

Please explain how!

- Math Trig -
**Laytin**, Tuesday, October 16, 2012 at 10:10amI know the answer but I don't understand the process. ! If you could explain the process without the answers?!

- Math Trig -
**Reiny**, Tuesday, October 16, 2012 at 10:40amplot the point (12,5) and join it to the origin.

draw a vertical line from the point to the x-axis

You now have a right-angled triangle with a base (x) of 12 and a height (y) of 5

Using Pythagoras, we can find the hypotenuse

h^2 = 12^2 + 5^2 = 169

h = 13

let the base angle be Ø

You should have learned the following definitions

sinØ = opposite/hypotenuse = 5/13

cosØ = adjacent/hypotenus = 12/13

tanØ = opposite/adjacent = 5/12

of course ...

cscØ = 13/5

secØ = 13/12

cotØ = 12/5

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