Posted by Laytin on .
Find the values of the six trigonometric functions of an angle in standard position if the point with coordinates (12, 5) lies on its terminal side?
Please explain how!

Math Trig 
Laytin,
I know the answer but I don't understand the process. ! If you could explain the process without the answers?!

Math Trig 
Reiny,
plot the point (12,5) and join it to the origin.
draw a vertical line from the point to the xaxis
You now have a rightangled triangle with a base (x) of 12 and a height (y) of 5
Using Pythagoras, we can find the hypotenuse
h^2 = 12^2 + 5^2 = 169
h = 13
let the base angle be Ø
You should have learned the following definitions
sinØ = opposite/hypotenuse = 5/13
cosØ = adjacent/hypotenus = 12/13
tanØ = opposite/adjacent = 5/12
of course ...
cscØ = 13/5
secØ = 13/12
cotØ = 12/5