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January 31, 2015

January 31, 2015

Posted by **Laytin** on Tuesday, October 16, 2012 at 9:56am.

Please explain how!

- Math Trig -
**Steve**, Tuesday, October 16, 2012 at 11:12amif the hypotenuse is at (12,5), the hypotenuse is length 13:

sinθ = 5/13

cosθ = 12/13

tanθ = 5/12

secθ = 1/cosθ = 13/12

cscθ = 1/sinθ = 13/5

cotθ = 1/tanθ = 12/5

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