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Posted by on Tuesday, October 16, 2012 at 5:02am.

the height from where the water bomb will be released on the overpass is 4.5 m and the target student is 170 cm tall. the student realises that, as his target will be moving, he must release the water bomb when his friend is a certain horizontal distance from the point of impact. if his friend is walking towards the overpass at 2m/s calculate the distance

  • PHYSICS!!!!!!!!!!!!!!!! - , Thursday, October 18, 2012 at 3:33pm

    h = ho - (Vo*t + 0.5g*t^2 = 1.71 m.
    4.5 - (0 + 4.9t^2 = 1.71
    -4.9t^2 = 1.71 - 4.5 = -2.79
    t^2 = 0.5694
    Tf = 0.755 = Fall time.

    d = 2m/s * 0.755s = 1.51 m.

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