Posted by sara on Tuesday, October 16, 2012 at 2:53am.
same question ....
http://www.jiskha.com/display.cgi?id=1333489636
just change the necessary numbers
since you have a calculus class, you probably ought to do it Reiny's way, but sometimes a little simplification can save you some work:
If the man is x away from pole, ad his shadow length is s, then using similar triangles,
s/2 = (x+s)/6
s = 1/2 x
so, ds/dt = 1/2 dx/dt
since the tip of the shadow is x+s from the pole, it is moving at
dx/dt + ds/dt = dx/dt + 1/2 dx/dt = 3/2 dx/dt = 3/2(1.4) = 2.1 m/s
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